batman equation

\documentclass[a4paper,french,10pt]{article}
\usepackage[francais]{babel}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{url}

\begin{document}

The Batman equation - \url{http://i.imgur.com/CNy9J.jpg}

\begin{equation*}
\begin{split}
\left( \left(\frac{x}{7}\right)^2 \sqrt{\frac{||x|-3|}{|x|-3}} + \left(\frac{x}{3}\right)^2 \sqrt{\frac{|y+\frac{3\sqrt{33}}{7}|}{y+\frac{3\sqrt{33}}{7}}} -1 \right) \cdot \left( |\frac{x}{2}| - \left(\frac{3\sqrt{33}-7}{112}\right)x^2 -3 + \sqrt{1-(||x|-2|-1)^2}-y \right) \\ \cdot \left( 9 \sqrt{\frac{|\left(|x|-1\right)\left(|x|-.75 \right)|}{\left(1-|x|\right) \left(|x|-.75\right)}} \right) \cdot \left( 3|x|+.75 \sqrt{\frac{|\left(|x|-.75\right)\left(|x|-.5\right)|}{\left(.75-|x|\right)\left(|x|-.5 \right)}}-y \right) \\ \cdot \left(2.25 \sqrt{\frac{|\left(|x|-1\right)\left(|x|- .75\right)|}{\left(1-|x|\right)\left(|x|-.75\right)}} \right) \cdot \left( \frac{6\sqrt{10}}{7} + \left(1.5 - .5|x|\right) \sqrt{\frac{||x|-1|}{|x|-1}} - \frac{6\sqrt{10}}{14} \sqrt{4-\left(|x|-1\right)^2}-y \right)=0
\end{split}
\end{equation*}

\end{document}