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By: a guest | Mar 14th, 2010 | Syntax: MySQL | Size: 1.27 KB | Hits: 53 | Expires: Never
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  1. SELECT c.idContract,c.cl_nome, c.cl_cognome,  c.Users_idUsers, sca.idService, sca.data_attivazione, sca.data_disattivazione,sca.salePrice, sca.startUpPrice,
  2. sca.provvigione, s.period, s.idService, s.description, u.name, u.lastname, sca.unatantum,
  3. DATEDIFF( IFNULL(sca.data_disattivazione, NOW( )) , sca.data_attivazione) timeFrame,  0  timeFrameFrom,  0  timeFrameTo,  0  timeFrameDisTo,  0  timeFrameDisFrom, sca.qty,  sca.data_attivazione=sca.data_attivazione hasUnatantum,
  4. GROUP_CONCAT(dop.qty) dqty, GROUP_CONCAT(dop.qtyPaid) dqtyPaid,
  5. GROUP_CONCAT(dop.qtyOnSale) dqtyOnSale, GROUP_CONCAT(dop.qtyOnSalePaid) dqtyOnSalePaid, GROUP_CONCAT(dop.begin_date) dbegin_date, MAX(cp.dataPagamento) dataUltimoPagamento,  0 timeFramePayFrom,  0 timeFramePayTo
  6. FROM Contract c
  7. JOIN ServicesContractsAssociation sca ON ( sca.idContract = c.idContract AND sca.status =2 )
  8. JOIN Services s ON ( s.idService = sca.idService )
  9. JOIN Users u ON ( u.idUsers =Users_idUsers  )
  10. LEFT JOIN DefaultOnPayments dop ON (dop.idService=sca.idService  && dop.idContract=sca.idContract)
  11. LEFT JOIN CommissionsPayments cp ON (u.idUsers = cp.idUser);
  12. WHERE  1   AND sca.idUser IN (1,3,4,5,6,7,8,9,10,11,12,13)   AND sca.idUser=13        
  13. GROUP BY sca.idContract, sca.idService <?xml version="1.0" encoding="UTF-8"?>