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By: a guest on
Aug 6th, 2012 | syntax:
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find and replace repeating string in database
[data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
[data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
[data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
[data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
[data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
the text of the article
[data.... ]
[data.... ]
[data.... ]
select distinct mycolumn from mytable;
select mycolumn from mytable group by mycolumn;
DELETE t
FROM t
LEFT JOIN t AS t2 ON (t.content = t2.content AND t.id > t2.id)
WHERE t2.id;
SELECT * FROM t;
+----+---------+
| id | content |
+----+---------+
| 1 | abc |
| 5 | abc123 |
| 9 | abc123 |
| 13 | abc |
| 17 | abc |
+----+---------+
SELECT * FROM t;
+----+---------+
| id | content |
+----+---------+
| 1 | abc |
| 5 | abc123 |
+----+---------+