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difference between pointer and reference in c?
address    01   02   03
             +----+----+----+...
data within  | 23 | 6f | 4a |
             +----+----+----+...

char c = 'z';  // 'z' is 7a in hex

address    01   02   03
             +----+----+----+...
data within  | 7a | 6f | 4a |
             +----+----+----+...

char* p = &c;  // point at c

address    01   02   03
             +----+----+----+...
data within  | 7a | 01 | 4a |
             +----+----+----+...

char& r = c;

const char& r = c;
r = 'y';  // error; you may not change c through r
c = 'y'   // ok. and now r == 'y' as well

| Address  | Value          |
|----------|----------------|
|0x1111    |0x1112          | <-- Pointer!
|0x1112    |42              | <-- Pointed value
|0x1113    |42              | <-- Some other value

mov rax, [r8]

void add(int* x)
{
    *x = *x + 7;
}

void cppadd(int& x)
{
    int a = 7;
    x = &a; // doesn't work.
}

int a;
int* b = &a;
// b holds the memory address of a, not the value of a.

int a;
int* b = &a;
// b is a reference to a.

int a;
int* b = &a;
int c = *b;
// c dereferences b, meaning that c will be set with the value stored in the address that b contains.