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Sep 22nd, 2011
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  1. '''
  2. Find the greatest product of five consecutive digits in the 1000-digit number.
  3. '''
  4.  
  5. n = '''\
  6. 73167176531330624919225119674426574742355349194934
  7. 96983520312774506326239578318016984801869478851843
  8. 85861560789112949495459501737958331952853208805511
  9. 12540698747158523863050715693290963295227443043557
  10. 66896648950445244523161731856403098711121722383113
  11. 62229893423380308135336276614282806444486645238749
  12. 30358907296290491560440772390713810515859307960866
  13. 70172427121883998797908792274921901699720888093776
  14. 65727333001053367881220235421809751254540594752243
  15. 52584907711670556013604839586446706324415722155397
  16. 53697817977846174064955149290862569321978468622482
  17. 83972241375657056057490261407972968652414535100474
  18. 82166370484403199890008895243450658541227588666881
  19. 16427171479924442928230863465674813919123162824586
  20. 17866458359124566529476545682848912883142607690042
  21. 24219022671055626321111109370544217506941658960408
  22. 07198403850962455444362981230987879927244284909188
  23. 84580156166097919133875499200524063689912560717606
  24. 05886116467109405077541002256983155200055935729725
  25. 71636269561882670428252483600823257530420752963450'''
  26. n = n.replace('\n','')
  27.  
  28. maxProduct = -1
  29. for i in xrange(len(n)-4):
  30.     product = int(n[i])*int(n[i+1])*int(n[i+2])*int(n[i+3])*int(n[i+4])
  31.     if product > maxProduct:maxProduct = product
  32. print maxProduct
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