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By: a guest on May 5th, 2012  |  syntax: None  |  size: 0.34 KB  |  hits: 9  |  expires: Never
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  1. django admin sort foreign key field list
  2. class MyModelAdmin(admin.ModelAdmin):
  3.     def formfield_for_foreignkey(self, db_field, request, **kwargs):
  4.         if db_field.name == "school":
  5.             kwargs["queryset"] = School.objects.order_by('name')
  6.         return super(MyModelAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)
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