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By: a guest on Apr 29th, 2012  |  syntax: None  |  size: 0.40 KB  |  hits: 19  |  expires: Never
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  1. Split a string and add into `tuple`
  2. import re
  3.  
  4. 1. tuple(map(lambda i: i, re.findall('[d]{2}', '012345'))) # ('01', '23', '45')
  5.  
  6. 2. tuple(i for i in re.findall('[d]{2}', '012345')) # ('01', '23', '45')
  7.        
  8. s = "012345"
  9. [s[i:i + 2] for i in range(0, len(s), 2)]
  10.        
  11. tuple(s[i:i + 2] for i in range(0, len(s), 2))
  12.        
  13. s = '012345'
  14. map(''.join, zip(*[iter(s)]*2))
  15.        
  16. tuple(map(''.join, zip(*[iter(s)]*2)))
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