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how to get last string '22' using java
public class a {

    public static void main(String[] args) {
        String a = "12345aaaa##22";
        String b = a[-2:];
        System.out.println(b);
      }
}

String lastToChars = input.substring(input.length()-2);
// if you need that number as integer
int value = Integer.parseInt(lastToChars);

String charsAfterDelimiter = input.split("##")[1];

String a = "12345aaaa##22";
System.out.println(a.substring(a.length() - 2));

String a = "12345aaaa##22";
int value = Integer.ParseInt(a.substring(a.length() - 2);
System.out.println(value);

String a = "12345aaaa##22";
String number = "22";
int position = a.SlastIndexOf("22");
int value = Integer.ParseInt(position+number.lenght());
System.out.println(value);