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bash Command line substitution in for loop
`#!/bin/bash
 for((i=1;i<"$#";i++)) do
        printf "Position %s of argumentArray has  %s n", $i  $(($i))
  done`

for((i=1;i<"$#";i++)) do
printf "Position %s of argumentArray has  %s n", $i  $"$( eval echo $i )"
done

./test.sh  first second third

Position 1 of argumentArray has  1
Position 1 of argumentArray has  2
Position 1 of argumentArray has  3

Position 1 of argumentArray has  first
Position 1 of argumentArray has  second
Position 1 of argumentArray has  third

for((i=1;i<="$#";i++))
  do
      case "$($i)" in
       .......

arguments=($@)
for ((i = 0; i < ${#arguments[@]}; i++)); do
    echo "arguments[$i] = ${arguments[$i]}"
done

$ ./args.sh first second third
arguments[0] = first
arguments[1] = second
arguments[2] = third

for((i=1;i<=$#;i++)) do
    printf "Position %s of argumentArray has  %s n" $i  "${!i}"
done