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Aug 21st, 2013
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  1. long largest_product_in_grid(string num, int w, int h) {
  2.  
  3.     long largest = 0;
  4.  
  5.     char[] cval = to!(char[])(num);
  6.  
  7.     int[][] ival = new int[][](w,h);
  8.     int curCVal = 0;
  9.  
  10.     for(int i = 0; i < ival[0].length; i++) {
  11.         for(int j = 0; j < ival.length; j++) {
  12.         writeln("i: ", i, ", j: ", j);
  13.             ival[j][i] = to!(int)(cval[curCVal]) - '0';
  14.        
  15.             if(curCVal < cval.length-1) curCVal++;
  16.         }
  17.     }
  18.    
  19.     writeln(ival);
  20.    
  21.     return largest;
  22. }
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