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Nov 26th, 2014
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  1. def index_of_2nd_largest(alist):
  2. second_largest=0
  3. largest=0
  4. n1=len(alist)
  5.  
  6. i=0
  7. index=0
  8. while i< n1:
  9.  
  10. if largest<alist[i]:
  11. largest=alist[i]
  12. n2=i
  13.  
  14. elif second_largest<alist[i]:
  15. second_largest=alist[i]
  16. index=i
  17.  
  18.  
  19.  
  20. i+=1
  21. return index
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