- sql SELECT IN with like
- select * from salary where employeename like (select name from employee)
- select distinct s.*
- from salary s
- join employee e on s.employeename like '%' + e.name + '%'
- select * from salary where emp_name like '%aj'
Don't like ads? PRO users don't see any ads ;-)
Text below is selected. Please press Ctrl+C to copy to your clipboard. (⌘+C on Mac)
create a new version of this paste
RAW Paste Data