Advertisement
Guest User

Untitled

a guest
Nov 14th, 2015
200
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 2.09 KB | None | 0 0
  1. #include <iostream>
  2. #include <vector>
  3. #include <cmath>
  4.  
  5.  
  6. using namespace std;
  7. int n = 0;
  8.  
  9.  
  10. int index(int x, int y)
  11. {
  12. return x*n +y;
  13. }
  14. int main(){
  15.  
  16. int m = 0;
  17. cin >> n;
  18. cin >> m;
  19.  
  20. int**grid = new int*[n]();
  21. for(int i =0;i<n;i++)
  22. {
  23. grid[i] = new int[n]();
  24. for(int j =0;j<n;j++)
  25. {
  26. cin >> grid[i][j];
  27. }
  28.  
  29. }
  30.  
  31.  
  32.  
  33. // int** charms = new int*[m]();
  34. int* safe = new int[n*n]();
  35. for(int i =0;i<m;i++)
  36. {
  37. int* charms = new int[3]();
  38. cin >> charms[0];
  39. cin >> charms[1];
  40. cin >> charms[2];
  41. for(int x = -charms[2]; x <= charms[2]; x++)
  42. {
  43. for(int y = charms[2] - abs(x); y >= -(charms[2] - abs(x)); y-- )
  44. {
  45. int x1 = charms[0] + x;
  46. int y1 = charms[1] + y;
  47. if(x1 > 0 && y1 > 0 && x1 < n+1 && y1 < n+1)
  48. safe[(x1-1)*n + y1 - 1] = 1;
  49. }
  50. }
  51. }
  52.  
  53.  
  54. //cout << "SAFE\n";
  55. for(int i =0;i<n;i++)
  56. {
  57.  
  58. }
  59.  
  60. int* dp = new int[n*n];
  61. int out = 0;
  62. if(safe[0] == 1 && safe[n*n -1] == 1)
  63. {
  64.  
  65. for(int i =0;i<n;i++)
  66. {
  67. for(int j =0;j<n;j++)
  68. {
  69.  
  70. if(i==0 && j== 0 && safe[0] == 1)
  71. {
  72. dp[index(i,j)] = grid[0][0];
  73.  
  74. }
  75. else if(safe[i *n +j] == 1)
  76. {
  77. if(j>0 && safe[i *n +j-1] == 1 && i>0 && safe[(i -1)*n +j] == 1)
  78. {
  79. dp[index(i,j)] = max(dp[index(i-1,j)], dp[index(i,j-1)]) != -10001 ? grid[i][j] + max(dp[index(i-1,j)], dp[index(i,j-1)]) : -10001;
  80. }
  81. else if(j>0 && safe[i *n +j-1] == 1)
  82. {
  83. dp[i*n + j] = dp[index(i,j-1)] != -10001 ? grid[i][j] + dp[index(i,j-1)]: 0;
  84. }
  85. else if(i>0 && safe[(i -1)*n +j] == 1)
  86. dp[i*n + j] = dp[index(i-1,j)] != -10001 ? grid[i][j] + dp[index(i-1,j)]: 0;
  87. else
  88.  
  89. dp[index(i,j)] = -10001;
  90. // cout << i<<","<<j<<":" << dp[i*n + j][0]<<":"<< dp[i*n + j][1]<<"\n";
  91. }
  92. else
  93. {
  94. dp[index(i,j)] = -10001;
  95. }
  96. }
  97. }
  98. /*for(int i =0;i<n;i++)
  99. {
  100. for(int j=0;j<n;j++)
  101. {
  102. cout << dp[index(i, j)];
  103. cout << " ";
  104. }
  105. cout << "\n";
  106. }*/
  107. out = dp[n*n - 1];
  108. if(out == -10001)
  109. cout << "NO\n";
  110. else{
  111. cout << "YES\n";
  112. cout << out;
  113. }
  114. }
  115. else
  116. cout << "NO\n";
  117.  
  118. }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement