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Veil-Evasion Error Kali 1.0.9

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Oct 22nd, 2014
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Python 1.21 KB | None | 0 0
  1. =========================================================================
  2.  Veil-Evasion | [Version]: 2.4.3
  3. =========================================================================
  4.  [Web]: https://www.veil-framework.com/ | [Twitter]: @VeilFramework
  5. =========================================================================
  6.  
  7. Traceback (most recent call last):
  8.   File "./Veil-Evasion.py", line 43, in <module>
  9.     controller = controller.Controller(oneRun=False)
  10.   File "/usr/share/veil-evasion/modules/common/controller.py", line 129, in __init__
  11.     self.LoadPayloads()
  12.   File "/usr/share/veil-evasion/modules/common/controller.py", line 145, in LoadPayloads
  13.     module = d[name].Payload()
  14.   File "/usr/share/veil-evasion//modules/payloads/native/backdoor_factory.py", line 27, in __init__
  15.     self.shellcode = shellcode.Shellcode()
  16.   File "/usr/share/veil-evasion/modules/common/shellcode.py", line 42, in __init__
  17.     self.LoadModules()
  18.   File "/usr/share/veil-evasion/modules/common/shellcode.py", line 109, in LoadModules
  19.     cmd, options = eval(")".join(line.strip().replace("true", "True").split("OptString.new(")[1].split(")")[:-1]))
  20.   File "<string>", line 0
  21.    
  22.     ^
  23. SyntaxError: unexpected EOF while parsing
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